Question

a car travels at a uniform velocity of 50ms-1 for 10 sec and is bought to rest in 5 sec Calculate the retardation and distance travelled in 15 sec

Answer 1

u = 50m/s

v = 0

t = 5 second

a = ?

v = u+at

0=50+5a

-50=5a

a= -50/5=-10

therefore the retardation is 10m/s^2

Distance for 10seconds = 10*50=500m

Distance for remaining 5 second =

S = ut+1/2*at^2

S = 250+1/2*(-10)*5

S = 250+(-25)

S = 225 m

Total distance = 225+500= 725m

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