Question

A car travels at constant acceleration of 5 m/s ^ 2 from rest. How far has it travelled by the time it reached the velocity of 72 km/h * (20 m/s)?​

Answer 1

Step-by-step explanatioFormulae,

ut+21at2=50t

0+21×5×t2=50t

t=50×52=20s

v2=u2+2as

v2=0+2×5×(50×20)

v2=10000

∴v=100m/s

Answer 2

Given:-

$\sf\orange{initial \: velocity,u = {5ms}^{ - 1}}$

$\sf \green{acceleration, \: a = {2ms}^{ - 2} }$

Apply kinematic equation of motion:-

$\sf \red{s = ut + \frac{1}{2} {at}^{2}}$

$\sf \blue{s = 5 \times 10 + \frac{1}{2} \times {10}^{2} }$

$\purple\bigstar \fbox \mathtt \orange{ = 150 \: m}$

Hence in first 10 second card travel 150m!