Question

A car travels due north a distance of 12km then turns due west and travels 5kms. The resultant displacement of the car is :

4 points


​

Answer 1

Answer:

Let AB be the distance travel to North and BC be the distance travel to West

so, displacement = AC = 13

Explanation:

so, ABC is a right triangle.

(AB) ^2 + (BC) ^2 = (AC) ^2

(12) ^2 + (5) ^2 = (AC) ^2

144 + 25 = (AC) ^2

169 = (AC) ^2

AC = √169

AC = 13

so, required displacement = 13 ANS

If this solution is helpful to you so, please like and follow me.

Answer 2

Answer:

The resultant displacement of car is 13 km

Explanation:

By pythagoras theory,

$h ^{2} = p ^{2} + b ^{2}$

$h ^{2} = 12^{2} + 5^{2}$

$h ^{2} = 144 + 25$

$h ^{2} = 169$

$h = \sqrt{169}$

$h = \sqrt{ {13}^{2} }$

$h = 13$

Therefore,

The resultant displacement of car is 13 km.

IF YOU LIKE THIS SOLUTION,PLEASE LIKE AND FOLLOW ME