Question

A car travels eastward at 20m/s for 40s and then accelerate at 14m/s² for 20s. Find the velocity and distance

Answer 1

Answer:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ speed=20 {ms}^{-1} \\ t_1 = 40s \\ a = 14 {ms}^{ - 2} \\ t_2 = 20s \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ velocity \: and \: distance \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ speed = \frac{distance}{time} \\ distance = speed \times time \\ = 20 \times 40 \\ = 800m \\ acceleration = \frac{velocity}{time} \\ velocity = acceleration \times time \\ = 14 \times 20 \\ = 280 \: {ms}^{ - 1} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$