a car travels first 10 km in 20 minutes and another 10 km in 30 minutes what is the average speed of the car in metre per second
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average speed =total distance/total time
total distance = 10+ 10=20km
total time=20+30 =50minutes=5/6 hr
av. speed=20÷5/6=24km/h
=24×5/18=20/3 m/s
total distance = 10+ 10=20km
total time=20+30 =50minutes=5/6 hr
av. speed=20÷5/6=24km/h
=24×5/18=20/3 m/s
suhaani4351:
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D1 = 10 km
T1 = 20 minutes
V1 =?
So V1 = D1/T1
= 10/20
=1/2 km/min
D2 = 10 km
T2 = 30 minutes
V2 =?
So V2 = D2/T2
= 10/30
= 1/3 km/min
Average Velocity = (V1+V2)/2
= (1/2+1/3)/2
Average Velocity = (5×2)/6
5/3 km/min Ans.
T1 = 20 minutes
V1 =?
So V1 = D1/T1
= 10/20
=1/2 km/min
D2 = 10 km
T2 = 30 minutes
V2 =?
So V2 = D2/T2
= 10/30
= 1/3 km/min
Average Velocity = (V1+V2)/2
= (1/2+1/3)/2
Average Velocity = (5×2)/6
5/3 km/min Ans.
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