A car travels first 450 kms of a journey at a speed of 90kmph and the remaining 750 km at a speed of 50kmph. find the average speed of the whole journey
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Answered by
8
Time taken for 450 km at a speed of 90 kmph
= 450/90 = 5 h
Tike taken for 750 km at a speed of 50 kmph
= 750/50 = 15 h
Total distance = 450 + 750 = 1200 km
total time = 5 + 15 = 20 h
so, average speed = total distance/total time
= 1200/20 = 60 kmph
= 450/90 = 5 h
Tike taken for 750 km at a speed of 50 kmph
= 750/50 = 15 h
Total distance = 450 + 750 = 1200 km
total time = 5 + 15 = 20 h
so, average speed = total distance/total time
= 1200/20 = 60 kmph
Answered by
1
Time taken for 450 km at a speed of 90 kmph
= 450/90 = 5 h
Tike taken for 750 km at a speed of 50 kmph
= 750/50 = 15 h
Total distance = 450 + 750 = 1200 km
total time = 5 + 15 = 20 h
so, average speed = total distance/total time
= 1200/20 = 60 kmph
= 450/90 = 5 h
Tike taken for 750 km at a speed of 50 kmph
= 750/50 = 15 h
Total distance = 450 + 750 = 1200 km
total time = 5 + 15 = 20 h
so, average speed = total distance/total time
= 1200/20 = 60 kmph
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