a car travels first 50 km with uniform motion of 45 km/hr and the next 50 km at the rate of 90 km/hr. find the average velocity of the car
Answers
Answer:
ANSWER
To complete 1km distance with speed =50kmhr it tkes time t
1
=
50
1
s
To complete 1km distance with speed =40kmhr it tkes time t
1
=
40
1
s
Average speed=
(1/50)+(1/40)
1+1
=44.44m/
GIVEN-
D1=50KM ,D2=50KM.
V1=45KM/H ,V2=90KM/H
SABSE PEHLE HME PURI JOURNEY KA TIME NIKALNA HOGA KYOKI TIME ,DISTANCE PURI JOURNEY KA SAME RAHEGI, SIRF SPEED CHANGE HOGI.
SO,TOTAL TIME=TOTAL DISTANCE/TOTAL SPEED(V1)
TOTAL TIME=100/45=20/9=T
HAMARA PURI JOURNEY KA TIME AA GYA .
AAB HME STARTING KE 50 KM KA TIME NIKALNA HOGA .
THE STEPS ARE AS FOLLOWS.
TIME FOR FIRST 50 KM=D1/V1
TIME FOR FIRST 50 KM=50/45=10/9=T1
AAB HUME ISE ENTIRE JOURNEY KE TIME SE MINUS KARNA HOGA.(JISSE HME NEXT 5OKM KA TIME PTA CHAL JAYEGA).
SO, TIME FOR REMAINING JOURNEY=(TOTAL TIME)-(FIRST 50 KM TIME)
=(20/9)-(10/9)
=(10/9)=T2
AAB HME AGLE 50 KM KA TIME PTA CHAL CHUKA HAI AUR DISTANCE BHI 50 KM MALUM HAI.(BAS SPEED NIKALNI HAI.)
SO, SPEED FOR REMAINING JOURNEY=(V2)/(T2)
=(90)/(10/9)
=(90X10)/(9)
=100 KM/H
HOPE YOU UNDERSTAND GUYS