Question

A car travels first half of the distance between two places with a speed of 60 km/h & rest
half of the distance with a speed of 40 km/h. Find the average speed of the car.​

Answer 1

Answer:

Average speed is V= time

ddistanc if a car travels first half with V 1

and second half of distance with V 2

then formula of average velocity is given by

V= V1+V2

2V 2 V 1

=

60+40

2∗60∗40

=48km/h

Answer 2

Given:

• A car travels first half of the distance between two places with a speed of 60 km/h & rest half of the distance with a speed of 40 km/h

To Find:

• The avarage speed of the car

Solution:

Here, we have given the speed of the car in the first half which is 60km/phr and the speed of the car in the second half which is 40km/phr So, Now we have to find the average speed of the car using suitable formulae which would help us in finding the average speed of the car.

${ \underline{ \frak{As \: we \: know \: that}}}$

$\: \: \: \: \: \: \star \pink{ \boxed{ \tt{average \: speed(v) = \frac{2 v_{1}v_{2}}{(v_{1} + v_{2})} }}}$

Here,

• V₁ = 60km
• V₂ = 40km

Substituting the values we get ,

$\longrightarrow \tt \: average \: speed = \frac{2(v_{1} \times v_{2})}{(v_{1} + v_{2})} \: \: \: \: \\ \\ \\ \longrightarrow \tt \: average \: speed = \frac{2 \times 60 \times 40}{60 + 40} \\ \\ \\ \longrightarrow \tt \: average \: speed = \frac{2 \times \: 2400 }{100} \: \: \: \: \\ \\ \\ \longrightarrow \tt \: average \: speed = \cancel \frac{4800}{100} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \dashrightarrow \tt \: average \: speed = \pink{48 \: km \: per \: hr}$

${ \underline{ \pmb{ \frak{hence \: the \: average \: speed = \pink{48km \: phr}}}}}$