a car travels from a stop to a stop with 30 km/h and than return 50km/h find the displacement of car , distance travel by the car ande average speed of the car
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As car returns to its initial position , so displacement will be ZERO .
AVERAGE speed is 2x30x50/80 = 300/8 = 37.5 km/h
distance traveled will be twice the distance from initial stop to final stop
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AVERAGE speed is 2x30x50/80 = 300/8 = 37.5 km/h
distance traveled will be twice the distance from initial stop to final stop
plz mark as brainliest
varandeepsahota:
thank you
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