A car travels from A to B and returns to its original position.
The distance between A and B is 2000 m.
0 Find the total displacement of the car. ♡
(1) The car takes 5 min to travel from A to B but takes 8 min to travel back
from B to A. Is the speed of the caf greater while going from A to B or while
travelling back from B to A?
in When can the magnitude of distance and displacement be equal for a body
in motion?
Answers
Answer:
Let the distance between A and B be x
Speed ¹ = 50kmph
therefore time taken = x/50
return journey
speed ²=40kmph
time taken = x/40
total distance travelled =x+x=2x km
displacement =0
average speed = total distance/total time
= 2x/(x/50+x/40)
= 2x÷[ x(40+50)/200]
= 2*200/90
= 45 kmph
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Answer:
The total displacement of the car is 0 as the car goes from A to B and again from B to A.
The speed of the car is greater is greater while going from A to B as time is inversely proportional to speed .(s=d/t)
Here distance remains the same while time changes.
The magnitude of distance and displacement will be same if the car travels in a straight path with uniform motion.
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