A car travels from A to B at 40km/hr. 7/4 hours later, another car starts from A, and travelling at 48km/hr, reaches B 15 minutes before the first car. The distance (in km) from A to B is:
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As we know,
Average speed = 2xy/(x + y)
∴ Average speed = (2 × 40 × 60)/(40 + 60) = 48 km/hr
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