A car travels from a to b at 50kmph on return journey along the same path it travels at 40kmph find it distance travelled, displacement,average speed
Answers
Answer:
Explanation: let the distance between A and B be x
Speed ¹ = 50kmph
therefore time taken = x/50
return journey
speed ²=40kmph
time taken = x/40
total distance travelled =x+x=2x km
displacement =0
average speed = total distance/total time
= 2x/(x/50+x/40)
= 2x÷[ x(40+50)/200]
= 2*200/90
= 45 kmph
A car travels from a to b at 50 km/hr and return back using the same pathway with a speed of 40 km/hr.
We have to find the distance travelled, displacement and average speed of the .
Let us assume that the distance covered by the car is 'x' km.
Since the car starts from A to B, then returns to A point again. So, the distance covered by the car is twice of the distance i.e. 2x km. Also, the initial and final points of the car are same i.e. A point. So, the displacement of the car is 0 km.
Now,
Average speed of defined as the ratio of total distance covered with respect to total time taken.
Time = Distance/Speed
t1 = x/50 hr and t2 = x/40 hr
Total time taken by car = t1 + t2
= x/50 + x/40
= x/10(1/5 + 1/4)
= x/10(9/20)
= 9x/200
Average speed = 2x/(9x/200)
= (2 × 200)/9
= 44.44
Therefore, the average speed of the car is 44.44 km/hr.