Question

A car travels from point A to B in 3 hours and written back to point a in 5 hours. Point A and B are 150 miles apart along a straight highway then calculate
1. Speed and velocity when it travel from A to B
2. Speed and velocity when a travel back B to A
3. Speed and velocity when it travel and returns
explain your answer in all three conditions...
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Answer 1

As the car finally reaches at its initial position again, thus net displacement of the car is zero   i.e  S=0  km

Total time taken       t=3+5=8h

∴  Average velocity       Vavg=S/t=0/10=0  km/h

Given that,

The time taken from A to B is 3 hours

The time from B to A = 5 hours

The total distance between A and B is 150 miles

The average velocity from A to B,

v=\dfrac{150}{3}=50\ mphv=

3

150

=50 mph

The average velocity from B to A,

v=\dfrac{150}{5}=30\ mphv=

5

150

=30 mph

As the velocity of an object is a vector quantity. It means when the car reaches the initial point, the displacement is 0. So, the average velocity is equal to 0.

Answer 2

Answer:

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