a car travels from stop A to B with a speed of 30km/h and then return backs to A with a speed of 50km/h.Find
1 displacement of the car
2 distance travelled by the car
3 average speed of the car
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Answer:
total distance is S
displacement is 0
AVERAGE VELOCITY IS 37.5 km/h
Explanation:
let distance A to B be s/2
distance between B to A is s/2
total distance is s/2 + s/2= s
Displacement will be s/2 - s/2 = 0
t1 = s1/v1
= s/2×30
= s/60
t2 = s2/v2
= s/2×50
= s/100
AVERAGE VELOCITY = total distance/total time
= s/s/60+s/100
= s/s/20(1/3+1/5)
= 20/5+3/15
= 20×15/8
=15×2.5
= 37.5 km/h
samyakjain336p8x3z5:
plzz mark brainliest
what is the distan ce
as no distance is given so we take total distance as a variable
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