Question

A car travels from stop A to B with a speed of 30km/hr and returns from B to A with a speed of 50km/hr . Find the distance and Avg speed. With explanation

Answer 1

Vav = 2(V1)(V2)/V1 + V2

= 2×30×50/30+50

= 300/80

= 30/8

= 3.125 km/h

Answer 2

Answer:

Step-by-step explanation:

For a to b let the distance be d1 and time be t1.

Forb to a let the distance be d2 and time be t2

Speed=distance/time

=d1/t1

Therefore, d1=speed ×time

30×t1

Speed=distance /time

50=d2/t2

Therefore, d2=50×t2

With the changing speed time is also changing but distance remains the same.

Therefore d1=d2

30×t1=50×t2

On solving equation we get t1=50 and t2=30

Therefore distance covered=50×30=1500

Now you can get t1 and t2 by using speed formula and take out average speed