Question

A car travels from stop A to stop 8 with a speed of 30 knyh and then returns to Awit
of 50 km/h. Find
(a) The displacement of the car.
(b) The distance travelled by the car.
(c) The average speed of the car.​

Answer 1

Answer:

Explanation:

Let the distance from A to B be x.

Then displacement of the car when it comes back to the same position is zero.

Distance travelled is 2x.

Time taken by the car when it moves from A to B is given by

t1 = Distance/Speed = x/30

Time taken by the car when it moves from B to A,

t2 = Distance/Speed = x/50

Total distance = 2x

Total time

= t1 + t2

= x/30 + x/50

= (5x + 3x)/150

= 8x/150

So, Average speed

= Total distance/Total time

= 2x/(8x/150)

= 37.5 km/hr

Same answer Given by me :-

https://brainly.in/question/21723

Answer 2

Answer:

suppose the distance from A to B = X .

then displacement of the car when it comes back to the same position is zero .

distance travelled is 2x .

time taken by the car when its moves from it to B is given by :

t1= distance /speed =x 30

taken time by the car when its moves from B to a .

t2= distance /speed = x/50

Total distance 2x

total time

= t1+12

=x/ 30 +x/50

8x/50

so the average speed

=Total distance/ total time

2x/(8x/150)

37.5 km/hr

Thanks.