Question

A car travels from stop A to stop B covering a distance of 100km in 3hrs and then returns back to A in a time 4hrs,Find 1)displacement of the car 2)distance travelled by the car 3)average speed of the car 4)average velocity of the car​

Answer 1

1) As the car returns back, displacement will be zero

2) Distance from Stop A to Stop B= 100km

Total distance = 100km + 100km

= 200km

3) Total distance= 200km

Total time = 3hr + 4hr

= 7hr

Average speed=

$\frac{total \: distance}{total \: time}$

$= \frac{200}{7}$

$28 \frac{4}{7} km/h \\ or \\ 28.57km/h$

4) Displacement= 0

Time= 7hr

Average velocity=

$\frac{displacement}{time}$

$= \frac{0}{7}$

$= 0$