A car travels from stop A to stop B with a speed of 30 km per hour and then returns back to A with a speed of 50 km per hour find the distance travelled by the car.
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Hello mate,
1st case. Given that from A to B the car is travelled with a speed of 30km/hr
⇒speed=distance/time
30=x/t.......[x=distance & t=time]
∴x=30t
2nd case. From B to A with a speed of 50km/hr
⇒50=x/t
∴x=50t
Total distance covered =50t+30tkm
or we can multiply either of the 2 distances above obtained by two because the car has travelled along the same path.
Hope the qn is answered
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