A car travels from stop a to stop B with a speed of 30 km per hour and then return back to point a with a speed of 50 km per hour find displacement of of the car
Answers
Answered by
4
zero is the displacement as initial position coincide with final position
Answered by
4
Displacement of the car is zero as it is returned to its initial position.
1) Distance travelled by the car
We have to know how long it took for the round trip to find the distance:Lets assume it took 12 hrs for the round trip:let d = the one way distance
Write a time equation; time = dist/speed+= 12
multiply by 150
150*+ 150*= 150(12)
Cancel the denominators and you have:5d + 3d = 18008d = 1800d = 1800/8d = 225 m one way or a total of 450 m round trip
Confirm this find the actual time each way225/30 = 7.5 hrs
225/50 = 4.5 hrs
total hr: 12
2) average speed
v = 30 km/h
t = s/v
t = x/30 h
v= 50km/h
s=x
t= x/50 h
total distance= x+x =2x
total time= x/30 +x/50 = 5x +3x/150 = 8x/150
average speed = 2x / (8x/150)
= 2x * 150/8x = 37.5 km/h
1) Distance travelled by the car
We have to know how long it took for the round trip to find the distance:Lets assume it took 12 hrs for the round trip:let d = the one way distance
Write a time equation; time = dist/speed+= 12
multiply by 150
150*+ 150*= 150(12)
Cancel the denominators and you have:5d + 3d = 18008d = 1800d = 1800/8d = 225 m one way or a total of 450 m round trip
Confirm this find the actual time each way225/30 = 7.5 hrs
225/50 = 4.5 hrs
total hr: 12
2) average speed
v = 30 km/h
t = s/v
t = x/30 h
v= 50km/h
s=x
t= x/50 h
total distance= x+x =2x
total time= x/30 +x/50 = 5x +3x/150 = 8x/150
average speed = 2x / (8x/150)
= 2x * 150/8x = 37.5 km/h
Similar questions