Question

A car travels from stop A to stop B with a speed of 30 km per hour and then return back to A with speed of 50 km per hour. Find (1)displacement of the car (2) distance travel by the car (3) average speed of the car

Answer 1

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Here is your answer...

Solution:-
•Distance is the shortest distance betweenthe final and initial position,and here final and initial position are same therefore the displacement will be '0'

Let the distance travelled from A to B be x
Total distance=2x

Now,time taken from A to B=
$time = \frac{distance}{speed}$
Here,distance is x and speed is 30 km/h
$time = \frac{x}{30}$

Time taken from B to A=
$= > \frac{x}{50}$
Now,
$average \: speed = \frac{total \: distance}{total \: time \: taken}$
$= > \frac{2x}{ \frac{x}{30} + \frac{x}{50 } } \\ = > \frac{2x}{ \frac{8x}{150} } \\ = > 2x \times \frac{150}{8x}$
$= > 37.5$
Hence,
Average speed=37.5km/h

Therefore,
Total Distance=
$= > 2 x \\ = > 2 \times 37.5 \\ = > 75m$
Hope it helps uh...✌️✌️✌️