Question

A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find (i) displacement of the car. (ii) distance traveled by the car. (iii) average speed of the car.​

Answer 1

Answer displacement = 0 and avg vel =

Explanation:

since the body goes from initial to final (a to b) and then comes back therefore the body comes back to the initial , and displacement is the shortest distance therefore 0

b let the distance travelled by the car from stop A to B = x km

The car travels from A to B and returns back to B. Thus,

total distance travelled = 2x km

Time while going from A to B = Distance travelled / Speed taken

                                         = x/30 hours

Time while returning from stop B to A = x/50 hours

therefore total time = 8x/150

or 4x/75 hrs

now avg speed = 2x*75/4x

that is 37.5 km/hr

and distance = 37.5*2 = 75 km

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