A car travels from stop A to stop B with a speed of 30 km/h in 3 hours and then returns back to A in 1 hour with a speed of 50 km/h. Find for the entire motion of the car
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car
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Answer:
(2) distance traveled by the car for the entire motion of the car
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(I) Displacement = 0
As the initial.and the final position of the car is the same
We know that displacement is the shortest distance covered between its initial and final position
(2) Let the distance covered by the car be x
As the car returns back to its initial position
total distance covered = 2x
(3) Avg speed = total distance/ time taken
total distance=2 x
total time = t1 + t2
t = d/v
t1 = x/ 30 t2 = x/50
total time = x/30+x/50= 8x/150
Avg speed
= 2 x / x( 8/150)
=2×150/8
=150/4
=37.5 m/s
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