Physics, asked by jagdishs123, 10 months ago

A car travels from stop A to stop B with a speed of 30 km/h and then returns to A with a speed of 50 km/h. Find a) displacement of the car. b) distance travelled by the car. c) average speed of the car.

Answers

Answered by Anonymous
26

A car travels from stop A to stop B with a speed of 30km/h and then returns back to stop A with a speed of 50km/h.

We have to find the-

(a) Displacement of the car.

(B) Distance travelled by the car.

(c) Average speed of the car.

Assume that the distance covered by the car is x km.

(a) Since the car starts from point A to B and then returns back to point A again using the same pathway. Final and initial of the car is same i.e. A point.

Therefore, the Displacement of the car is 0 km.

(B and c) Average speed is defined as the ratio of total distance covered with respect to total time taken.

As the distance covered by the car is same i.e. x km. From A to B distance covered is x km and from B to A distance covered is x km. So, the total distance covered by the car is 2x km.

Also,

Time = Distance/Speed

t1 = x/30 hr and t2 = x/50 hr

Total time taken = t1 + t2

= x/30 + x/50

= x/5(4/15)

= 4x/75

Average speed = 2x/(4x/75)

= (2*75)/4

= 37.5

Therefore, the average speed of the car is 37.5 km/hr.

Answered by BrainlyIAS
3

Given :

A car travels from stop A to stop B with a speed of 30 km/h and then returns to A with a speed of 50 km/h

To Find :

a) displacement of the car.

b) distance travelled by the car.

c) average speed of the car.

Solution :

a) displacement of the car

Given that , A car travels from stop A to B with a speed of 30 km/h and then returns to A with a speed of 50 km/h

So the initial and final positions are same .

We know that displacement is the shortest distance i.e., difference b/w final and initial positions .

Displacement of the car is zero .

b) distance travelled by the car

Let the distance covered by car to travel from stop A to B be " x "

So , distance b/w stop B to A is also " x "

Therefore the total distance travelled by car = Distance b/w stop A & B + Distance b/w stop B & A

Distance travelled by car = x + x = 2x

c) average speed of the car

Average Speed : It is defined as the total distance covered per total time .

Total Distance , D = 2x [ From b) ]

Time_A-B = Distance_A-B / Speed_A-B

⇒ Time_A-B = x / 30

Time_B-A = Distance_B-A / Speed_B-A

⇒ Time_B-A = x / 50

Now , Total Time , T = x / 30 + x / 50

⇒ T = 4 x / 75

Now , Average Speed = Total Distance , D / Total Time , T

⇒ A.Speed = 2x / ( 4 x / 75 )

⇒ A.Speed = 75/2

⇒ A. SPeed = 37.5 km/h

So the Average Speed of the car is 37.5 km/h

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