A car travels from stop A to stop B with a speed of 30 km/h and then back to A with a speed of 50 km/h. Find (a) displacement of the car (b) distance travelled by the car (c) average speed of the car
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Answered by
2
a) Displacement is zero (0).
b) distance travelled = distance between stop A and B multiply by 2
c) 40km/h
b) distance travelled = distance between stop A and B multiply by 2
c) 40km/h
Vedansh05:
explain it
displacement is zero because it's final and initial position both are same
I mean the 2 nd one
solve it
here time is not given so we have to calculate by thinking distance as x and multipling it by 2 bcoz its displacement is zero
so distance is 2x
Answered by
1
Hey!
there is your answer....
(a) : displacement is zero as there is the car starts from point A and also come back at point B . soo no displacement happened.
(b): distance travelled by car is total distance from a to b + total distance from b to a
(c) : average speed = total speed /2 = 50 +30/2 =80 /2 =40 km/h
there is your answer....
(a) : displacement is zero as there is the car starts from point A and also come back at point B . soo no displacement happened.
(b): distance travelled by car is total distance from a to b + total distance from b to a
(c) : average speed = total speed /2 = 50 +30/2 =80 /2 =40 km/h
solve the 2nd question
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