Question

A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of

50 km/h. Find

(i) Displacement of the car.

(ii) Distance travelled by the car.

(iii) Average speed of the car.​

Answer 1

Answer:

Displacement is the shortest distance between the initial and the final position. Here the car travels from stop A to B and return to stop A. Thus, the displacement of the car is 0 m/s

Explanation:

let the distance travelled by the car from stop A to B = x km. The car travel from A to B return back to B. Thus, total distance travelled = 2x km. Time while going from A to B = distance travelled / speed taken = x / 30 hours. Time while returning from B to A = x / 50 hours . Total time x / 30 + x / 50 = 8x/ 150

average speed = total distance / time taken

2x × 75 / 4x

average speed = 37.5 km/h

thus, total distance = 2x = 2 × 37.5 = 75 m