a car travels from stop a to stop b with a speed of 30 km /h and then returns back to a with a speed of 50 km / h find (i) displacement of the car (ii)distance travelled by the car (iii) average speed of the car
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Let the distance from A to B be x.
YED 69%
Then displacement of the car when it comes back to the same position is zero.
Distance travelled is 2x.
Time taken by the car when it moves from A to B is given by
t1 = Distance/Speed = x/30
Time taken by the car when it moves from B to A,
t2 = Distance/Speed = x/50
Total distance = 2x
Total time
=t+t2
= x/30 + x/50
= (5x + 3x)/150
= 8x/150
So, Average speed
= Total distance/Total time
= 2x/(8x/150)
= 37.5 km/hr
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