A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with
a speed of 50 km/h. Find
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car.
Answers
Answered by
4
I) total displacement =A-B
II) total distance =A+B
iii) average speed = 2 *50*30/T1+T2
II) total distance =A+B
iii) average speed = 2 *50*30/T1+T2
Answered by
8
(i)Displacement of the car is 0 ,as it again returns back to the initial point.
(ii) Distance traveled by the car is 80 km, as distance formula is speed× time
(iii) average speed of the car is 40km/ hr as the formula of average speed is( total distance traveled / total time taken)
hope ur doubt is cleared and ur satisfied wid mah answer....☺☺
(ii) Distance traveled by the car is 80 km, as distance formula is speed× time
(iii) average speed of the car is 40km/ hr as the formula of average speed is( total distance traveled / total time taken)
hope ur doubt is cleared and ur satisfied wid mah answer....☺☺
mradulb:
how canu solve this plz explain me
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