Question

A car travels from stop A to stop B with a speed of 30 km/h
and then returns back to A with a speed of 50 km/h. Find
(i) displacement of the car. (ii) distance travelled by
the car.
(iii) average speed of the car.

Answer 1

Answer:

Displacement is the shortest distance between the initial position and the final position. Here, the car travels from stop A to stop B and then returns back to stop A.

Thus, the displacement of the car is 0 m/s.

Let the distance travelled by the car from stop A to stop B = x km.

The car travels from stop A to stop B and

returns back to point A.

:: Total distance travelled = 2x km.

Time taken while going from stop A to stop B = Distance travelled / Speed taken

= x/30 hrs

Time taken while returning from stop B to stop A = Distance travelled / Speed taken.

= x/50 hrs.

Total time taken = x/30 +x/50

= (50x + 30x)/1500

= 80x/1500

= 8x/150

= 4x/75 hrs

Average speed = Total distance traveled/ total time taken.

= 2x x 75/4x

= 150x/4x

= 37.5 km/h.

Answer 2

Answer:

Let the distance from A to B be x.

Then displacement of the car when it come.

back to the same position is zero.

Distance travelled is 2x.

Time taken by the car when it moves fromnA

to B is given by

t1 Distance/Speed = x/30

Time taken by the car when it moves fromB

to A,

t2 Distance/Speed = x/50

Total distance 2x

Total time

=t1+ t2

= x/30 + x/50

= (5x +3x/150

8x/150

So, Average speed

= Total distance/Total time

= 2x/(8x/150)

37.5 km/hr

Explanation:

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