A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car.
Answers
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9
Ans: i)displacement of the car will be zero.Because car return back to its initial position.
ii) let at distance from A to B is x then fistance from B to A also x, so
distance travell by car=x+x
or
distance travell by car= t1x30 + t2x50
iii)average speed =total distance/total time
=t1x30+t2x50/t1+t2
ii) let at distance from A to B is x then fistance from B to A also x, so
distance travell by car=x+x
or
distance travell by car= t1x30 + t2x50
iii)average speed =total distance/total time
=t1x30+t2x50/t1+t2
Answered by
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Answer:
A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car.
displacement of the car = 0 because car return to same point from where it started.
to find distance travelled by car we need to know distance between A& B or time taken by car
let assume distance between A&B is 150 km
total distance covered = 150+150 =300 km
time taken a to b = 150/30 = 5 hr
time taken b to a = 150/50 = 3 hr
total time = 5 + 3 = 8 hrs
average speed = 300/8 = 37.5 km/hr
Explanation:
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