A car travels from stop A to stop B with a speed of 30km/hr and then returns back to Stop A with a Speed of 50km/hr. Find
i) displacement of the car.
ii) distance travelled by the car
iii) average speed of the car.
Answers
Let the distance from A to B be x.
Then displacement of the car when it comes back to the same position is zero.
Distance travelled is 2x.
Time taken by the car when it moves from A to B is given by
t1 = Distance/Speed = x/30
Time taken by the car when it moves from B to A,
t2 = Distance/Speed = x/50
Total distance = 2x
Total time
= t1 + t2
= x/30 + x/50
= (5x + 3x)/150
= 8x/150
So, Average speed
= Total distance/Total time
= 2x/(8x/150)
= 37.5 km/hr
A car travels from stop A with a speed of 30 km/hr and then returns back to stop B with a speed of 50 km/hr. What is the displacement of the car, the distance it traveled, and its average speed?
Where can I get an audio gear at an affordable price?
Let the distance from A to B be x.
Then displacement of the car when it comes back to the same position is zero.
But the distance travelled is 2x.
Time taken by the car when it moves from A to B is given by
t1 = Distance/Speed = x/30
Time taken by the car when it moves from B to A,
t2 = Distance/Speed = x/50
Total distance = 2x
Total time = t1 + t2 = x/30 + x/50 = (5x + 3x)/150 = 8x/150
So, Average speed = Total distance/Total time = 2x/(8x/150) = 37.5 km/hr