Question

A car travels from stop P to stop Q with a speed of 36 km/h and then returns back to stop P
with a speed of 72 km/h. Find--
1)displacement of the car.
2)average velocity of the car.
3)average speed of the .​

Answer 1

Answer:

1)0,2)0

Explanation:

displacement is the shortest distance so displacement is 0 since it returns back again

avg velocity is 0 since displacement is 0

To find speed we need time but time is not there so avg speed is not possible

Answer 2

Answer:

solved

Explanation:

1)displacement of the car = zero

2)average velocity of the car = 36 km/h - 72 km/h =  - 36 km/h

3)average speed of the car  = total distance ÷ total time

average speed of the car =  2d ÷ ( d/36 + d/72) = 2d ÷ 3d/72 = 48 km/h