Question

a car travels from stopA to stop b with a speed of 30km h and then return to a with a speed of 50km h find displacement of car, distance traveled by car, average speed of car

Answer 1

DISPLACEMENT OF THE CAR IS ZERO AS IT RETURNS TO ITS INITIAL POSITION .

AVERAGE SPEED = (2 X 30 X 50) /30 + 50  = 3000/80 = 37.5Km/h

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Answer 2

Let the distance from A to B x

then displacemant ahe of the car when it

Comes back to the Same position is zero

Distance travelled by car when it moves from A do B given by

t1= distance /Speed =x/30

time taken by the Car when it moves from a to b

t2= Distance/speed = x/50

total distance = 2x

Total time

= t1 + t2

= x/30 + x/50

= (5x +3x)/150

= 8x/150

So average speed

Total distance/Total time

= 2x/(8x/150)

= 33.5 km/hr