Question

a car travels half of the distance with constant velocity 40 kilometre per hour and another of a half with a constant velocity of 60 km per hour along a straight line the average velocity of the car is

Answer 1

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Answer 2

let x be distance 
then...x/2 be half distance

now time t1 taken by the car with a velocity 40 km/hr =x/80 hr ..(t=d×s)
now time t2 taken by the car with a velocity 60 km/hr =x/120 hr
avg velocity=total time /total distance
                   =(x/2+x/2)/ (x/80+x/120)
                   =(x) / (3x+2x)/240
                   =x×240/5x
                   =48km/hr is answer..


 I hope its help you...