Question

A car travels half the distance with constant velocity of
40 kmph and the remaining half with a constant velocity
60 kmph. The average velocity of the car in kmph is
(b) 45
(e) 48
(d) 50
(a) 40​

Answer 1

Answer:

s1 =40kmph

s2= 60kmph

av velocity = 2s1 s2 /(s1+s2)

= 2×40×60/(40+60)

= 2400/100

= 24kmph

Answer 2

Answer:

Let total distance travelled be 2x.

So time taken to travel first half is t1 = x/40

Similarly, time taken to travel second half is t2 = x/60

Now,we know that,

$avg \: velocity \: = \frac{total \: distance}{total \: time}$

$= \: \frac{2x}{ \frac{x}{40} + \frac{x}{60} }$

$\frac{2(40)(60)}{40 + 60}$

= 48 km/hr

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