Question

A car travels in linear direction with an average speed of 40 Km/hr between
points A – B and with an average speed of 60 Km/hr between
B – C. If the linear distance between AB is half of BC calculate the average speed of
the car for its entire journey.

Answer 1

Given

• Average Speed between A-B is 40Km/hr

• Average Speed between B-C is 60Km/hr

• Linear distance between AB is half of BC

To Find

• Average speed of the car for its entire journey.

Solution

____________________

Let the linear distance between B-C be x

then the linear distance between A-B be x/2 .

• Average speed A-B = 40 Km/hr
• Average speed B-C = 60 Km/hr

Distance = Total Speed × Time

$\sf \: →x+ \dfrac{x}{2} = 40+60 × 1× 1$

$\sf \: → \dfrac{2x + x}{2} = 100$

$\sf→3x=200$

$\sf \: →x= 66.666$

Distance between A-B = 66.6/2km

Distance between B-C = 66.6/2 = 33.33km

${ \bf Average \: speed= \dfrac { Total \: Distance }{Total \: time } }$

${ \sf Average \: speed= \dfrac { 66.66 + 33.33 }{1 + 1 } }$

${ \sf Average \: speed= \dfrac { 99.99 }{2 } }$

${ \sf Average \: speed≈50}$

• Average speed of the car for its entire journey is 50km/hr

Answer 2

Answer:

For explanation see in the attachment photos.

Average speed of the car for its entire journey is 50km/hr.

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