Question

a car travels initially at 20m s is accelerated to 40 m/s in 10 seconds. what is the acceleration of the car? how far does it travel during the 10s?

Answer 1

Given that,

• Initial velocity of the car = 20 m/s (u)

• Final velocity of the car = 40 m/s (v)

• Time = 10 seconds (t)

• Acceleration = ? (a)

we know,

⇒ Acceleration = v-u/t

⇒ Acceleration = 40 m/s - 20 m/s/ 10 sec

⇒ Acceleration = 20 m/s/10 sec

⇒ Acceleration = 2 m/s²

Therefore, the acceleration of the car is 2 m/s².

Distance travelled by the car =

Given that,

• Acceleration = 2 m/s² (a)

• Time = 10 seconds (t)

• Initial velocity = 20 m/s (u)

• Distance = ? (s)

We know,

⇒ s = ut + 1/2at²

⇒ s = (20 m/s)(10 sec) + 1/2(2 m/s²)(10 s)²

⇒ s = 200 m/s²+1 m/s²×10 s²

⇒ s = 200 m/s²+10m

⇒ s = 200 m

∴ The distance covered by the car in 10 seconds is 200 m.

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Answer 2

Answer:

acceleration is 2m/s

distance is 300m

Explanation:

d=vit=1/2at^2

d= 20x10+1/2 (2)(10)^2

d=200+ 1x10^2

d= 200+100

d=300