a car travels initially at 20m s is accelerated to 40 m/s in 10 seconds. what is the acceleration of the car? how far does it travel during the 10s?
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Given that,
- Initial velocity of the car = 20 m/s (u)
- Final velocity of the car = 40 m/s (v)
- Time = 10 seconds (t)
- Acceleration = ? (a)
we know,
⇒ Acceleration = v-u/t
⇒ Acceleration = 40 m/s - 20 m/s/ 10 sec
⇒ Acceleration = 20 m/s/10 sec
⇒ Acceleration = 2 m/s²
Therefore, the acceleration of the car is 2 m/s².
Distance travelled by the car =
Given that,
- Acceleration = 2 m/s² (a)
- Time = 10 seconds (t)
- Initial velocity = 20 m/s (u)
- Distance = ? (s)
We know,
⇒ s = ut + 1/2at²
⇒ s = (20 m/s)(10 sec) + 1/2(2 m/s²)(10 s)²
⇒ s = 200 m/s²+1 m/s²×10 s²
⇒ s = 200 m/s²+10m
⇒ s = 200 m
∴ The distance covered by the car in 10 seconds is 200 m.
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Answered by
0
Answer:
acceleration is 2m/s
distance is 300m
Explanation:
d=vit=1/2at^2
d= 20x10+1/2 (2)(10)^2
d=200+ 1x10^2
d= 200+100
d=300
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