A car travels north at 30 m/s for 10.0 min. it then travels south at 40 m/s for 20 min. what are the total distance the car travels and its displacement?
Answers
Answered by
2
Distance = 66 km or 66000 m.
Displacement = 51.264 km or 51264 m.
Explanation:
10 minutes = 10 × 60 = 600 seconds and
20 minutes = 20 × 60 = 1200 seconds.
Distance travelled by car in North direction
= speed × time
= 30 × 600 = 18000 m = 18 km.
Distance travelled in South direction
= 40 × 1200 = 48000 m = 48 km.
Total distance travelled by car = 18 + 48
= 66 km or 66000 m.
For the calculation of displacement,
18 km and 48 km will be legs of a right triangle.
Using Pythagoras-Theorem,
Displacement = √(18^2 + 48^2 )
= √[6^2(9 + 64)]
= 6√(73)
= 6 × 8.5440
= 51.264 km.
Hence, displacement of car = 51.264 km (approx)
Similar questions