A car travels successive one-third of its journey along a straight line with uniform speeds of u, v and w respectively. Calculate the average speed of the train.
Answers
Answer:
Explanation: Speed(s)=distance(d)/time(t)
Let us assume the total distance travelled to be 3x.
So the car travels x distance with each speed.
Since, s=d/t,
t=d/s
So the total time taken would be
T=x/40 + x/50 + x/60
Total distance, D=3x
Avg speed = D/T = 3x/( x/40 + x/50 + x/60 )
Cancel x from numerator and denominator and solve for average speed
plzz mark me as the brainliest answer
let distance to be covered is 1800.
then time taken for first 1/3 is T
1
=
10
600
=60sec
time taken for second 1/3 is T
1
=
20
600
=30sec
time taken for third 1/3 is T
1
=
60
600
=10sec
total time taken is 100 sec.
av velocity is
100
1800
=18km/s
this another way you can do it
Speed(s)=distance(d)/time(t)
Let us assume the total distance travelled to be 3x.
So the car travels x distance with each speed.
Since, s=d/t,
t=d/s
So the total time taken would be
T=x/40 + x/50 + x/60
Total distance, D=3x
Avg speed = D/T = 3x/( x/40 + x/50 + x/60 )
Cancel x from numerator and denominator and solve for average speed.
Hope it helps pls mark as brainliest.