Physics, asked by vahinimudumba, 8 months ago

A car travels the first half of a distance
between two
places at a speed of 30 km/h and the second half of the distance at 50km/h find the average speed of the body

Answers

Answered by jahnavigupta2005
2

Answer:

Let us assume that car has total distance of 2x km.

We know distance= speed× Time

Time = distance/speed

If a car travels first half of distance with speed of 30km/h

Distance = first half distance means 2x/2 = x km

Speed= 30 km/hr

Time taken to travel first half distance = x km/30 km per hr = x/30 hrs.

The car covers remaining half distance with speed of 50 km/hr

Distance = x km

Speed = 50 km/hr

Time taken to cover second half = x km/50 km per hr = x/50 hrs

Total time to cover 2x km distance = x/30 + x/50 = 80x /1500 hrs.

Average speed of car = total distance/total time

= 2x km /80x/1500 hrs

= 2x × 1500/80 x

=3000x/80x

= 3000/80

37.5 km/hr

Explanation:

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Answered by vanshika828
6

Answer:

Let the total distance=2x

The car travel in first half=30km/hr

Time taken in first half=X/30 hour

The car travel in second half=50km/hr

Time taken in second half=X/50 hour

Average speed=Total distance traveled÷Total time taken

=2x/X/30+x/50

=2x/5x+3x/150

=2x/8x×150

=150/4

=37.5km/hr

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