Question

a car travels the first if a distance with a speed of 10kmph the second third at 20 kmph and the last third at 60 kmph what is its mean speed over the entire distance​

Answer 1

Explanation:

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Answer 2

Answer:

18km/h

Explanation:

Let the total distance traveled be s.

Hence the time taken for first third of the distance

t1= (s/3)/v1

Similarly, the time taken for second third of the distance= t2= (s/3)/v2

and the time taken for last third of the distance

= t3= (s/3)/v3

Hence the mean speed over the distance=

s/(t1+t2+t3)

=3/{(1/v1)+(1/v2)+(1/v3)}

=18km/h

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