A car travels towards south for 8 minutes with a speed of v = 60 kmph, then turns and begins to move in a direction 53° north of west and travels at the same speed for 10 minutes.
Answers
Answered by
8
Answer: 6km
Explanation:
R=√(10²+8²-2×10×8 cos 37°)
R=√(164-128)
R=√36
R=6km
And if you go on drawing the diagram, you will find that the displacement is in West.
Answered by
1
The displacement of the car is 6km and the distance is 18km
Given:
The velocity of the car is 60kmph and in an angle at 53 speed is10 minutes
To Find:
The distance and the displacement of the car
Solution:
For first 8 minutes ,
S1 = v1t = 8000m
For next 10 minutes,
S2 = v2t = 10,000
Total displacement ,
S = -10000cos 53 i + 10000 sin53j - 8000j
= -6000i
Displacement is 6Km west
Distance of the car,
Distance = 8000 + 10000
Distance = 18Km
The displacement of the car is 6km and the distance is 18km
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