Question

. A car travels with a speed of 60 Km/hr for 15 minutes and then with a speed of 40 km/hr for the next 15 minutes. Find the total distance covered by the car.

Answer 1

Answer:

25 km

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Explanation:

Answer 2

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❇ Required Answer:

✏ GiveN:

• Firstly, cars travels with speed 60 km/hr for 15 minutes.
• Next, he travels with speed 40 km/hr for the next 15 minutes.

✏ To FinD:

• Find the total distance covered by car.

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❇ How to solve?

The question is asking the total distance covered with two different speeds for certain time intervals. This question is just a apply formula and get solution type question, so no need to worry. Just we need to know the formula i.e. speed, distance and time relation.

⏹ Speed, distance and time are related by:

$\large{ \boxed{ \rm{speed = \frac{distance}{time} }}}$

⏹ This can be written as:

$\large{ \boxed{ \rm{distance = speed \times time}}}$

⏹ Also if we want to do it directly, we need to know:

$\large{ \boxed{ \rm{avg.speed = \frac{total \: distance}{total \: time}}}}$

✏ Hence by using this formula, let's solve this question.

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❇ Solution:

In the first case:

• Speed = 60 km/hr
• Time travelled = 15 minutes.

As the speed is in hr, so we need to convert the time in minutes into time in hour.

$\large{ \rm{ \longrightarrow \: 60 \: minutes = 1 \: hour}} \\ \\ \large{ \rm{ \longrightarrow \: 15 \: minutes = \frac{1}{4} hour}}$

Now, by using formula,

$\large{ \rm{ \longrightarrow \: distance = 60 \: km {h }^{ - 1} \times \frac{1}{4} hr}} \\ \\ \large{ \rm{ \longrightarrow \: distance = \boxed{ \rm{ \red{15 \: km}}}}}$

Distance travelled with speed 60 km/hr = 15 km

In the second case:

• Speed = 40 km/hr
• Time travelled = 15 minutes = 1/4 hour

Now by using formula,

$\large{ \rm{ \longrightarrow \: distance = 40 \: km {h}^{ -1 } \times \frac{1}{4}hr}} \\ \\ \large{ \rm{ \longrightarrow \: distance = \boxed{ \red{ \rm{10 \: km}}}}}$

Distance travelled with speed 40 km/hr = 10 km

✝️ Total distance travelled by the car =

• 15 km + 10 km = 25 km (Ans)

$\large{ \therefore{ \underline{ \underline{ \orange{ \rm{Hence \: solved \: \dag}}}}}}$

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