A car travels with a uniform velocity of 20 m/s for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find: (i) The distance which the car travels before the brakes are applied (ii) The retardation (iii) The distance travelled by the car after applying the brakes.
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Retardation is obtained using the formula "v = u - a×t " , where v is final speed which is zero in this case,
u is initial speed , a is retardation and t is time
(1) retardation a = u/t = 25/10 = 2.5 m/s2 .
(2) distance travelled before applying break = 25×5 = 125 m
(3) distance S travelled after applying break is given by, S = u×t - (1/2)×a×t2 = 25×10 - (1/2)×2.5×100 = 125 m
Step-by-step explanation:
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