A Car travels with a Uniform Velocity of 20km/h for 3h.
to North then it stops for 2h after taking rest the car
Changes its direction to South travel with velocity of
30km/h for 4 hour.
a,Draw T-t graph
b,find the total distance travelled by the car
C,find the displacement of the Car
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☆Solution:
a) Draw V-t graph.
》refer the attachment ! for graph.
》put v on y-axis and t on x-axis.
》draw according to data given in the question .
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b) find the total distance travelled by the car.
》area of V-t graph gives total distance or displacement covered.
》Here in the graph as the car has changed direction, it displacement will get lessen due to negative area in the graph.
》but distance will be the sum of all area magnitude
》area of graph= (area of 1st rectangle) + (area of 2nd rectangle)
》area = ( 20km/h × 3h) + ( 30km/h × 4h)
》area = 60km + 120 km
》distance = 180 km.
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c) find the displacement of the Car.
》area = positive area - negative area
》area = (60 km) - (120 km)
》displacement = - 60 km.
☆negative sign indicates here that net displacement is in south direction (as we'd considered south as a negative axis)
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