a car travels with a uniform velocity of 25 m s for 5 s the brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s find
the distance which the car travels before the brakes are applied
the retardation
the distance travelled by the car after applying the brakes
Answers
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1) s/t=25/5=5m
2). 0-25/10= -2.5(retardation=2.5)
3). 2 (-2.5)S=0-625
-5s=-625
s=125m
2). 0-25/10= -2.5(retardation=2.5)
3). 2 (-2.5)S=0-625
-5s=-625
s=125m
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