A car travels with a uniform velocity of 50m/s for 10 seconds. The brakes are then applied and car is uniformly retarded. It comes to rest in further 8s.Draw a graph of velocity against time. Use this graph to find total distance travelled.
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Answer:
Given, u=20m/s
t
1
=5s
t
2
=8s
Graph: (Refer to Image)
(1) Distance travelled in first 5 sec= area of ABDE= 20×s=80m
(2) Distance travelled after the brakes are applied (area of BCD)=
2
1
×8×5=20m
(3) Total distance travelled= AreaofABCDE+AreaofBCD=80+20=100m
(4) Acceleration during the first 5 sec= 0, because uniform velocity.
(5) Acceleration during the last 8 sec= v=0,u=20m/s,t=8sec
⇒v=u+at⇒0=20+a(8)
⇒a=−2.5m/s
2
(slope of the line DC)
solution
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