Question

A car travels with a velocity 10 ms-1 and accelerates at 5 ms-2. Calculate
the final velocity when it has travelled 30 m.

Answer 1

Answer:

Here,

Initial velocity, u = 10 m/s

Acceleration, a = 5 m/s^2

Distance, s = 30 m

We know that,

2as = v^2 - u^2

2×5×30 = v^2 - 10^2

300 = v^2 - 100

v^2 = 400

v = 20

The final velocity is 20 m/s.

Answer 2

AnswEr:

Given,

• Initial velocity, u = 10 m $\sf{s}^{-1}$
• Distance, s = 30 m
• Acceleration, a = 5 m $\sf{s}^{-2}$
• Final Velocity, v = ?

$\star$ $\underline\text{Using\:\:third\:\:equation\:\:of\:\:motion:-}$

$\tt = {v}^{2} = {u}^{2} + 2as \\ \\ \tt = {v}^{2} = {10}^{2} + 2 \times 5 \times 30 \\ \\ \tt {v}^{2} = 100 + 300 \\ \\ \tt \: v = \sqrt{400} \\ \\ \tt \: v = 20 \: m {s}^{ - 1}$

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Velocity :-

• It is the speed in given direction.

• Velocity = $\sf\dfrac{Displacement}{Time}$

• SI unit is ( meter / second ) .. ( m/s ).

• Velocity is a vector quantity its value when either its magnitude or direction changes.