A car travels with a velocity 10m/s and accelerates at 5m/s^2. Calculate the final velocity when it has travelled 30m?
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Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec^2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v^2 = u^2 + 2as
=> v^2 = 10^2 + 2 × 5 × 30
=> v^2 = 100 + 300
=> v^2 = 400
=> v = √400
=> v = 20 m/sec
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ANSWER =
FINAL VELOCITY = 20 m/sec
_____________________________
___________________________
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec^2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v^2 = u^2 + 2as
=> v^2 = 10^2 + 2 × 5 × 30
=> v^2 = 100 + 300
=> v^2 = 400
=> v = √400
=> v = 20 m/sec
_____________________________
ANSWER =
FINAL VELOCITY = 20 m/sec
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kvnmurty:
Good. Perhaps you could save your time and effort by writing fewer steps of calculations. They are simple.
I wanted to make my answer very clear so that doubts doesn't arise in the mind of Quetionier
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44
HOPE THIS HELPS!! congo
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