A car travels with a velocity of 5 ms. It then accelerates uniformly and travels a distance of 50 m. If the velocity reached is 15 ms ', find the acceleration and the time to travel this distance. please answer this question in a good way
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Answers
Answer:
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec
2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v
2
=u
2
+2as
v
2
=10
2
+2×5×30
v
2
=100+300
v
2
=400
v =
400
v = 20 m/sec
ANSWER =
FINAL VELOCITY = 20 m/sec
Step-by-step explanation:
Answer:
\Large{\underline{\sf{Required \; Answer :}}}
RequiredAnswer:
As per the provided information in the given question, we have :
Initial velocity, u = 5 m/s
Distance covered, s = 50 m
Final velocity, v = 15 m/s
We have to find the acceleration and time taken.
By using the 3rd equation of motion,
➛ v² — u² = 2as
v denotes final velocity
u denotes initial velocity
a denotes acceleration
s denotes distance
➛ (15)² – (5)² = 2 × a × 50
➛ 225 – 25 = 100a
➛ 200 = 100a
➛ 200 ÷ 100 = a
➛ 2 m/s² = a (Answer)
Now, by using the 1st equation of motion,
➛ v = u + at
v denotes final velocity
u denotes initial velocity
a denotes acceleration
t denotes time
➛ 15 = 5 + 2t
➛ 15 – 5 = 2t
➛ 10 = 2t
➛ 10 ÷ 2 = t
➛ 5 seconds = t (Answer)
Therefore, acceleration of the car is 2 m/s² and time taken by the car is 5 seconds.
Step-by-step explanation:
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