Question

A car travels with an average speed of 23 m/s for 82 s. Which of the following could NOT have been the car's displacement? *
2 points
1,700 m east
2,000 m west
1,600 m north
1,500 m south

Answer 1

The answer is '2000 m west'.

Explanation:

as we know , displacement s= v×t (shortest path travelled) s= 23 ×82

s= 1886 m

this is the shortest distance the car could travel. Therefore, 2000m can't be possible with the given information.

Answer 2

Given: A car travels with an average speed of 23 ms⁻¹ for 82 s.

To find: Option that could not have been the car's displacement.

Solution:

• According to the formula of speed,

        $s = \frac{d}{t}$

• Here, s is the speed of the car, d is the distance covered by it and t is the time taken.
• Rearranging it,

        $d = s * t$

           $= 23ms^{-1} * 82 s$

           $= 1886m$

• So, 1886m is the minimum distance that can be covered by the car with the given speed and in the given time interval.
• 1700m east, 1600m north and 1500m south are distance that are less than the minimum distance and hence are possible.
• But 2000m is not possible.

Therefore, 2000m could not have been the car's displacement.